Chemistry, asked by Manmohan1995, 9 months ago

When dil HNO3 gets electrolysed will H+ or NO3- have more charge

Answers

Answered by RAthi21
29

hello!

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In dilute HNO 3

In dilute HNO 3

Oxidation potential of OH − > oxidation potential of NO 3−

Oxidation potential of OH − > oxidation potential of NO 3−

Oxidation potential of OH − > oxidation potential of NO 3−

Oxidation potential of OH − > oxidation potential of NO 3− ∴OH − oxidises to O 2

Oxidation potential of OH − > oxidation potential of NO 3− ∴OH − oxidises to O 2

Oxidation potential of OH − > oxidation potential of NO 3− ∴OH − oxidises to O 2 at anode in the following way:

Oxidation potential of OH − > oxidation potential of NO 3− ∴OH − oxidises to O 2 at anode in the following way: 4OH − →2H 2

Oxidation potential of OH − > oxidation potential of NO 3− ∴OH − oxidises to O 2 at anode in the following way: 4OH − →2H 2

Oxidation potential of OH − > oxidation potential of NO 3− ∴OH − oxidises to O 2 at anode in the following way: 4OH − →2H 2 O+O 2 +4e −

Oxidation potential of OH − > oxidation potential of NO 3− ∴OH − oxidises to O 2 at anode in the following way: 4OH − →2H 2 O+O 2 +4e −

Oxidation potential of OH − > oxidation potential of NO 3− ∴OH − oxidises to O 2 at anode in the following way: 4OH − →2H 2 O+O 2 +4e − H + reduces to H 2

Oxidation potential of OH − > oxidation potential of NO 3− ∴OH − oxidises to O 2 at anode in the following way: 4OH − →2H 2 O+O 2 +4e − H + reduces to H 2

Oxidation potential of OH − > oxidation potential of NO 3− ∴OH − oxidises to O 2 at anode in the following way: 4OH − →2H 2 O+O 2 +4e − H + reduces to H 2 at cathode in the following way:

Oxidation potential of OH − > oxidation potential of NO 3− ∴OH − oxidises to O 2 at anode in the following way: 4OH − →2H 2 O+O 2 +4e − H + reduces to H 2 at cathode in the following way: 2H + +2e − →H 2

Answered by PriyaRaiXI
0

Answer:

Dear please take help from above answer

It is correct...

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