When excess of SnCl₂ is added to a solution of HgCl₂, a
white precipitate turning to grey is obtained. This grey colour
is due to the formation of
(a) Hg₂Cl₂ (b) SnCl₄
(c) Sn (d) Hg.
Answers
Answered by
0
This grey colour is due to the formation of Hg. So option d is correct.
Explanation:
When excess SnCl₂ is added to HgCl₂ white precipitates are turning to grey and this is due to the formation of mercury (Hg). This mercury is in metallic form.
Chemical equation:
2HgCl₂ + SnCl₂ → SnCl₄ + Hg₂Cl₂ (White precipitate)
Chemical equation: (excess SnCl₂)
Hg₂Cl₂ + SnCl₂ → SnCl₄ + 2Hg (grey precipitate)
Similar questions