when four times a number is added to the square of the Same number, the result is 96, what is the number?
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Lets assume the number be x.
4x + x^2 = 96
=> x^2 + 4x-96 = 0
=> (x-8)(x+12) = 0,
so x = 8 or -12.
Check: 4*8 +*^2 = 32+64 = 96. Correct.
(-12)^2–4*12 = 144–48 = 96. Correct.
The number is 8 or -12.
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4x + x^2 = 96
=> x^2 + 4x-96 = 0
=> (x-8)(x+12) = 0,
so x = 8 or -12.
Check: 4*8 +*^2 = 32+64 = 96. Correct.
(-12)^2–4*12 = 144–48 = 96. Correct.
The number is 8 or -12.
__________________________
Hope that helps!!!
Please mark me as brainliest....
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