When hydrogen is burnt in oxygen to form sulhur iv oxide and water hi ow does the oxidation number of sulphur change
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Answer:
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Explanation:
Hydrogen sulphide burns in air to form sulphur dioxide: 2H2S + 3O2 → 2H2O + 3SO2. In this reaction, the sulphur is oxidized from -2 to +4. In the reaction H2S + 2O2 → H2SO4 + 790 kJ/mol, the oxidation is from -2 to +6. This reaction is very exothermic, but does not happen when H2S is burned. Hydrogen sulphide is said to be a reducing agent in these reactions. On the other hand, +6 sulphur, as in sulphuric acid, is a strong oxidizing agent. In the reaction Cu + 2H2SO4 → CuSO4 + 2H2O + SO2, the copper is oxidized from 0 to +2, while one sulphur atom is reduced from +6 to +4. The hot concentrated acid soaks up the water, while the sulphur dioxide is evolved, so the reaction goes to completion. Sulphur furnishes very good examples of oxidation and reduction.