Question

When hydrogen is passed over heated copper(ii) oxide, copper and steam are formed. write the balanced chemical eq with physical states?

Answer 1

Metallic copper and water vapour will be formed when hydrogen is passed over heated copper(II) oxide.

CuO + H2 = Cu + H2O

Hydrogen reduces cupric oxide to free metal in this reaction.

Answer 2

Answer:

CuO(s)+H2(g) --> Cu(s)+H2O(g)

Explanation:

it is a kind of redox /displacement reaction as H2 displaces CuO to form Cu and H2O. also hydrogen gas reduces the compound. here H2 is reducing agent and substance reduced is CuO.

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