when I minus is oxidised by MnO4 minus in an acidic and faintly alkaline medium, I minus is converted into respectively?
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KMnO4 acts as an oxidising agent in alkaline medium. When alkaline KMnO4 is treated with KI, iodide ion is oxidised to IO3-.
In acidic medium, the iodide will oxidize to molecular iodine:
2MnO4- + 10 I- + 16H+ -> 2Mn2+ + 5 I2 + 8H2O
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