Question

When I take po.o po.o it turns red.

Answer 1

Answer:

Using the formulas

Using the formulasA

Using the formulasA=

Using the formulasA=π

Using the formulasA=πr

Using the formulasA=πrl

Using the formulasA=πrl+

Using the formulasA=πrl+π

Using the formulasA=πrl+πr

Using the formulasA=πrl+πr2

Using the formulasA=πrl+πr2l

Using the formulasA=πrl+πr2l=

Using the formulasA=πrl+πr2l=r

Using the formulasA=πrl+πr2l=r2

Using the formulasA=πrl+πr2l=r2+

Using the formulasA=πrl+πr2l=r2+h

Using the formulasA=πrl+πr2l=r2+h2

Using the formulasA=πrl+πr2l=r2+h2Solving for

Using the formulasA=πrl+πr2l=r2+h2Solving forA

Using the formulasA=πrl+πr2l=r2+h2Solving forAA

Using the formulasA=πrl+πr2l=r2+h2Solving forAA=

Using the formulasA=πrl+πr2l=r2+h2Solving forAA=π

Using the formulasA=πrl+πr2l=r2+h2Solving forAA=πr

Using the formulasA=πrl+πr2l=r2+h2Solving forAA=πr(

Using the formulasA=πrl+πr2l=r2+h2Solving forAA=πr(r

Using the formulasA=πrl+πr2l=r2+h2Solving forAA=πr(r+

Using the formulasA=πrl+πr2l=r2+h2Solving forAA=πr(r+h

Using the formulasA=πrl+πr2l=r2+h2Solving forAA=πr(r+h2

Using the formulasA=πrl+πr2l=r2+h2Solving forAA=πr(r+h2+

Using the formulasA=πrl+πr2l=r2+h2Solving forAA=πr(r+h2+r

Using the formulasA=πrl+πr2l=r2+h2Solving forAA=πr(r+h2+r2

Using the formulasA=πrl+πr2l=r2+h2Solving forAA=πr(r+h2+r2)

Using the formulasA=πrl+πr2l=r2+h2Solving forAA=πr(r+h2+r2)=

Using the formulasA=πrl+πr2l=r2+h2Solving forAA=πr(r+h2+r2)=π

Using the formulasA=πrl+πr2l=r2+h2Solving forAA=πr(r+h2+r2)=π·

Using the formulasA=πrl+πr2l=r2+h2Solving forAA=πr(r+h2+r2)=π·5

Using the formulasA=πrl+πr2l=r2+h2Solving forAA=πr(r+h2+r2)=π·5·

Using the formulasA=πrl+πr2l=r2+h2Solving forAA=πr(r+h2+r2)=π·5·(

Using the formulasA=πrl+πr2l=r2+h2Solving forAA=πr(r+h2+r2)=π·5·(5

Using the formulasA=πrl+πr2l=r2+h2Solving forAA=πr(r+h2+r2)=π·5·(5+

Using the formulasA=πrl+πr2l=r2+h2Solving forAA=πr(r+h2+r2)=π·5·(5+12

Using the formulasA=πrl+πr2l=r2+h2Solving forAA=πr(r+h2+r2)=π·5·(5+122

Using the formulasA=πrl+πr2l=r2+h2Solving forAA=πr(r+h2+r2)=π·5·(5+122+

Using the formulasA=πrl+πr2l=r2+h2Solving forAA=πr(r+h2+r2)=π·5·(5+122+5

Using the formulasA=πrl+πr2l=r2+h2Solving forAA=πr(r+h2+r2)=π·5·(5+122+52

Using the formulasA=πrl+πr2l=r2+h2Solving forAA=πr(r+h2+r2)=π·5·(5+122+52)

Using the formulasA=πrl+πr2l=r2+h2Solving forAA=πr(r+h2+r2)=π·5·(5+122+52)≈

Using the formulasA=πrl+πr2l=r2+h2Solving forAA=πr(r+h2+r2)=π·5·(5+122+52)≈282.74334

Using the formulasA=πrl+πr2l=r2+h2Solving forAA=πr(r+h2+r2)=π·5·(5+122+52)≈282.74334cm²

Answer 2

Explanation:

hope it helps you ... Sorry I can't understand your question