When is an equation called an identity. Prove the trignometric identity 1+tan^2A=sec^2A
lkomesh:
1+Tan^2A = 1 + Sin^2A/Cos^2A = (Cos^2A+Sin^2A)/Cos^2A
since Cos^2A + Sin^2A = 1
1/Cos^2A= Sec^2A
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Answers
Answered by
1
L.H.S.
1+tan²A
1+sec²A-1
sec²A prove it.
1+tan²A
1+sec²A-1
sec²A prove it.
Answered by
0
tanA=perpendicular/base
secA=hypotenuse/base
1+tan^2
1+p^2/b^2
b^2+p^2/b^2
h^2/b^2
sec^2
hence proved
plz Mark it as a brainliast ok
secA=hypotenuse/base
1+tan^2
1+p^2/b^2
b^2+p^2/b^2
h^2/b^2
sec^2
hence proved
plz Mark it as a brainliast ok
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