When it is completely dehydrated (curso4,5h2,cuso4+5h2o)
(At wts. are Cu =64 s=32 O = 16, H=1)
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The molecular weight of water H
2
O=2(1)+16=18.
When 1 mole of CuSO
4
⋅5H
2
O is heated, 5 moles of water are lost.
The molecular weight of CuSO
4
⋅5H
2
O=64+32+4(16)+5(18)=250 g/mol
Mass of water lost =5(18)=90 g
Percentage loss of mass of CuSO
4
⋅5H
2
O=
250
90
×100=36 %.
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