Question

when kx^2+9x^2+4x -8 is divided by x+3 it leaves remainder -20, then what is the value of k?​

Answer 1

Answer:

x +3=0

x= -3

k(-3)^2 +9(-3)^2 + 4(-3)-8 = -20

k(9) + 81-12-8 = -20

k(9)+ 81-20 = -20

k(9) +81 = -20 +20 = 0

k9 = -81

k = -81/9

the value of k = -9

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