When lower limit is constant
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0
Step-by-step explanation:
let sin(4x2+5) इसमे 5 constant
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17
The upper limit is less than the lower limit. This is opposite of the usual situation, so simply switch the limits and put a minus sign in front. Then the new definite integral will be positive for the obvious reasons and combined with the new minus sign, this yields a negative result for the whole thing.
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