Question

When one mole of mixture of A_(2) &B_(2) allowed to react according to given reaction 2A_(2)(g)+3B_(2)(g)rarr2A_(2)B_(3)(s)+200 unit energy Calculate maximum energy released in this process-

Answer 1

Answer:

(i) 200 molecules of B will react with 200 atoms of A and 100 atoms of A will remain unreacted. Hence, B

2

is the limiting reagent.

(ii) 2 moles of A will react with 2 moles of B

2

and 1 mole of B

2

will remain unreacted. Thus, A is the limiting reagent.

(iii) 100 atoms of A will react with 100 molecules of B

2

. Thus, both reagents are present in stoichiometric amounts.

(iv) 2.5 mole of B

2

will react with 2.5 mole of A and 2.5 mole of A will remain unreacted. Hence, B

2

is the limiting reagent.

(v) 2.5 moles of A will react with 2.5 moles of B

2

and 2.5 moles of B

2

will remain unreacted. Thus, B

2

is the limiting reagent.

Explanation:

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