Question

When origin is shifted to (5.-2).
find the equation
xy + 2x-5y-11=0 in
new system​

Answer 1

Answer:

xy + 2x - 5y - 11 = 0 = -1

Step-by-step explanation:

Given,

Point = (5, -2)

Here,

Abscissa (x) = 5

Ordinate (y) = -2

Now by applying the values of x and y, we get,

xy + 2x - 5y - 11 = 0

=> 5(-2) + 2(5) - 5(-2) - 11 = 0

=> -10 + 10 + 10 - 11 = 0

=> 10 - 11

=> -1

Hence, xy + 2x - 5y - 11 = 0 = -1