Question

when ozone react with stannous chloride in presence of hydrochloride acid ​

Answer 1

Balance the reaction of SnCl2 + O3 + HCl = SnCl4 + H2O using this ... Stannous Chloride (tin(ii) Chloride) + Ozone + Hydrochloric Acid = Tin(iv) . follow me and mark me in brainliest

Answer 2

When ozone ( O$_{3}$ ) reacts with stannous chloride ( SnCl$_{2}$ ) in the presence of hydrochloric acid ( HCl ) , stannic chloride ( SnCl$_{4}$ ) is formed along with water ( H$_{2}$O ) .

The balanced chemical equation is given below -

3 SnCl$_{2}$ + O$_{3}$ + 6 HCl → 3 SnCl$_{4}$ + 3 H$_{2}$O

• In this reaction , ozone ( O$_{3}$ ) acts as an oxidizing agent and stannous chloride ( SnCl$_{2}$ ) acts as a reducing agent .
• This reaction is an example of an oxidation-reduction ( redox ) reaction .