Question

When p=2,q=-4,r=5find the value of (p+q+r)²,p²+q²+r²+2pq+2pr+2rp​

Answer 1

Answer:

9 and 9

Step-by-step explanation:

• p=2, q=-4, r=5

       (p + q + r)² = [2 + (-4) + 5]² = (2 - 4 + 5)² = (7 - 4)² = 3² = 9

•   p=2,q=-4,r=5

    p² + q² + r² + 2pq + 2qr + 2rp​

  =  2² + (-4)² + 5² + (2 * 2 * -4) + (2 * -4 * 5) + (2 * 5 * 2)

  =  4 + 16 + 25 - 16 - 40 + 20

  = 9