Question

When p(x) =x^3-3x^2+4x+32 is divided by x+2 the remainder is -???

Answer 1

Answer:

4

Step-by-step explanation:

$x + 2) {x}^{3} - 3 {x}^{2} + 4x + 32( {x }^{2} \\ \: \: \: \: \: \: \: \: \: \: \: \: {x}^{3} + 2 {x}^{2} \\ x + 2) - 5 {x}^{2} + 4x + 32( - 5x \\ \: \: \: \: \: \: \: \: \: \: \: - 5 {x}^{2} - 10x \\ x + 2)14x + 32(14 \\ \: \: \: \: \: \: \: \: \: \: \: 14x + 28 \\ = > remainder \: is \: 4$

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Answer 2

Answer:

The remainder is 4 .

Step-by-step explanation:

Given ,

x+2=0

x= -2

Now,

P(x)=x^3-3x^2+4x+32

P(-2)=(-2)^3-3(-2)^2+4(-2)+32

= -8 - 12 -8 +32

= -20 + 24

= 4

Therefore , the reaminder is 4 .