Question

When point charge of 6microcolumb is moved two points in electric field work done is 1.85*10-5 joule potential difference between the points is

Answer 1

Answer:

3 volts.

Explanation:

q=6×10^-6 c

W=1.85×10^-5 joule

W = q(∆v)

∆v= w÷q

=1.85 × 10^-5 ÷ 6 × 10^-6

=0.30×10

∆v =3 volts.