Question

When potassium iodide solution is added to a solution of lead nitrate in atest tube a precipitate is formed. What is tge colour of this precipitate ?Name the compound precipitated. Write the balanced chemical equation for this reaction . List two types of reaction in which this reaction can be placed?

Answer 1

The colour of this precipitate formed is yellow

The compound precipitated is lead iodide

Chemical reaction:

KI+Pb(NO3)2-----------》Pb(I)2+KNO3

Types of reaction are:

1.Double displacement reaction

2.Precipitation reaction

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Answer 2

Answer: a) yellow

b) Silver iodide

c) $2KI(aq)+Pb(NO_3)_2(aq)\rightarrow PbI_2(s)+2KNO_3(aq)$

d) double displacement and precipitation

Explanation:

A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.

$KI(aq)+Pb(NO_3)_2(aq)\rightarrow PbI_2(s)+KNO_3(aq)$

The precipitates of $PbI_2$ are yellow in colour and the chemical name for the precipitate is lead iodide.

The balanced chemical equation for this reaction is:

$2KI(aq)+Pb(NO_3)_2(aq)\rightarrow PbI_2(s)+2KNO_3(aq)$

The reaction is called as double displacement as exchange of ions take place and precipitation reaction as one of the product formed is solid in nature and do not solubilize in the solvent.