Biology, asked by sarayrehalaa, 3 months ago

When [S] = Km, the velocity of an enzyme catalyzed reaction is about?

Select one:

a. 0.1 Vmax

b. 0.9 Vmax

c. 0.4 Vmax

d. 0.7 Vmax

e. 0.5 Vmax

Answers

Answered by oshogarment

Answer:

How to calculate the km and Vmax values of an enzyme when I have substrate/product inhibition?

Hello,

Could anyone please help me in calculating the Km and Vmax values of an enzyme (I am working on dihydrofolate reductase DHFR) when I have substrate/product inhibition?

I see the inhibition on (specific activity nmol/min/mg to substrate concentration µM) curve, with substrate concentrations near the theoretical Vmax. (I mean the calculated Vmax by ignoring the inhibition).

(I attached a link of the curve)

- More details:

the Km of my enzyme is about 1µM. (in case I ignored the inhibition).

The specific activity with 5µM substrate is 2µM/min/mg. (in my case this is Vmax when I ignore the inhibition).

The specific activity with 10µ substrate is 1,7µM/min/mg. (it is lower here, that means here we have inhibition).

The specific activity with 20µM substrate is 1,5µM/min/mg. (again inhibition).

I don't know what is the right method to calculate the Vmax and Km for that enzyme and substrate with that inhibition phenomenon, waiting kindly for your guiding.

Explanation:

Answered by boneedemuimi

Answer: a

Explanation:

It's 80%

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