When silent electric discharge is passed through O2 gas, it converts into O3. If the density of final sample
is 20 times the density of hydrogen gas under similar conditions, calculate the mass percent of O2 in the
final sample
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Answered by
9
Answer:
40%
Explanation:
vd O²=16
vdO³=24
vd mix=20
so let moles of O²:O³=n:1 (or clearly n=1)
20=(16n+24) /(n+1)
»n=1
mass%=(16n/(16n+24)) ×(100%)
=40%
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1
Explanation:
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