Chemistry, asked by vinayak1266, 10 months ago

When So2 is passed into an acidified potassium dichromate solution the oxidation numbers of sulphur and chromium in the final products are

Answers

Answered by coolguyorionazm
2

Answer:

Explanation:

When Sulphur dioxide is passed through an acidified K2Cr2O7 solution ,the oxidation state of sulphur changes to (3) +4 to +6.

Explanation:

For occurance oxidation, the occurance of reduction is also important. (Cr2O4) -2 {valency is -2} is used as K2Cr2O7.

The half reaction which is also the oxidation reaction is performed.

(Cr2O4) -2+8H +6e-->2Cr+3 + 4H2O

S reduces I SO2. The half reaction which is also reduced reaction is performed.

SO2+2H2O-->SO4-2 +4H+ 2e

SO 2 becomes SO4-2

Let oxidation state of S be X then,

X+4(-2) =-2

X=6

Oxidation state of sulphur is +6.

Answered by jaswasri2006
0

Explanation:

The oxidation number of chromium in potassium dichromate is +6

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