Question

When SO2 was a passed through an acidified K2Cr2O7 solution

Answer 1

Answer: Here's your answer

Explanation:

When Sulphur dioxide is passed through an acidified K2Cr2O7 solution ,the oxidation state of sulphur changes to (3) +4 to +6. Explanation: For occurance oxidation, the occurance of reduction is also important.

Answer 2

Answer:

Sulpur dioxide turns into acidifiwd potassium dichromate from orange to green reduced

chromium +4 to +3