Chemistry, asked by sunilmore7003, 10 months ago

When SO2 was a passed through an acidified K2Cr2O7 solution

Answers

Answered by maniyachawla12
0

Answer: Here's your answer

Explanation:

When Sulphur dioxide is passed through an acidified K2Cr2O7 solution ,the oxidation state of sulphur changes to (3) +4 to +6. Explanation: For occurance oxidation, the occurance of reduction is also important.

Answered by boby0909
0

Answer:

Sulpur dioxide turns into acidifiwd potassium dichromate from orange to green reduced

chromium +4 to +3

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