Question

When sodium borohydride reacts with iodine in dimethyl ether solvent, the product is​

Answer 1

Answer:

Explanation:

First, iodine is reacting with one sodium borohydride, so you get borane, sodium iodide, and hydrogen iodide. Then hydrogen iodide is reacting with another sodium borohydride, so you get another borane and another sodium iodide, plus some hydrogen. All that borane is actually the stuff that reduces the acid to alcohol.