Chemistry, asked by mdtoufiktoufik742, 3 months ago

When sodium tert butoxide and methyl iodide are heated the product formed is

Answers

Answered by atul20972
5

Answer:

When potassium tert-butoxide and methyl bromide are heated, the product formed is. Isobutylene.

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Answered by qwstoke
0

When sodium tert-butoxide (NaOtBu) and methyl iodide (CH3I) are heated together, the product formed is tert-butyl methyl ether (MTBE), which is an organic compound with the chemical formula (CH3)3COCH3.

The reaction can be represented by the following equation:

NaOtBu + CH3I → (CH3)3COCH3 + NaI

In this reaction, sodium tert-butoxide acts as a strong base and abstracts a proton from methyl iodide to form the corresponding alkoxide ion intermediate. The alkoxide ion then attacks the methyl group of the methyl iodide, leading to the formation of tert-butyl methyl ether and sodium iodide as a byproduct.

MTBE is commonly used as a gasoline additive to improve combustion efficiency and reduce emissions. It is also used as a solvent and a chemical intermediate in the production of other organic compounds.

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