When sodium tert butoxide and methyl iodide are heated the product formed is
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Answer:
When potassium tert-butoxide and methyl bromide are heated, the product formed is. Isobutylene.
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When sodium tert-butoxide (NaOtBu) and methyl iodide (CH3I) are heated together, the product formed is tert-butyl methyl ether (MTBE), which is an organic compound with the chemical formula (CH3)3COCH3.
The reaction can be represented by the following equation:
NaOtBu + CH3I → (CH3)3COCH3 + NaI
In this reaction, sodium tert-butoxide acts as a strong base and abstracts a proton from methyl iodide to form the corresponding alkoxide ion intermediate. The alkoxide ion then attacks the methyl group of the methyl iodide, leading to the formation of tert-butyl methyl ether and sodium iodide as a byproduct.
MTBE is commonly used as a gasoline additive to improve combustion efficiency and reduce emissions. It is also used as a solvent and a chemical intermediate in the production of other organic compounds.
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