Question

WHEN SULPHUR IN THE FORM OF S8(g)IS HEATED AT 900K,THE INITIAL PARTIAL PRESSURE OF S8(g) WHICH WAS 1 ATM FALLS BY 29% AT EQUILIBRIUM.THIS IS BECAUSE OF CONVERSION OF SOME S8(g) TO S2(g).FIND KP OF THE REACTION.S8(g)....4S2(g)

Answer 1

The given equilibrium reaction,

$S_{8}(g) <==> 4 S_{2} (g)$

The initial pressure of $S_{8}$ = 1 atm

The equilibrium pressure of $S_{8}$ = $1 atm - \frac{29}{100} (1 atm) = 0.71 atm$

Setting up the ICE table to find out equilibrium constant,