Chemistry, asked by avaneesh5116, 9 months ago

When t-butyl alcohol is treated with an equimolecular mixture of HBr & HCl, which product will be predominated product.

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Answered by revagupta0332

Answer:

Explanation:

The order of reactivity of alcohols is 3° > 2° > 1° methyl.

The order of reactivity of the hydrogen halides is HI > HBr > HCl (HF is generally unreactive).

The reaction is acid catalyzed. Alcohols react with the strongly acidic hydrogen halides HCl, HBr, and HI, but they do not react with nonacidic NaCl, NaBr, or NaI. Primary and secondary alcohols can be converted to alkyl chlorides and bromides by allowing them to react with a mixture of a sodium halide and sulfuric acid:

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When t-butyl alcohol is treated with an equimolecular mixture of HBr & HCl, which product will be predominated product.​

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When t-butyl alcohol is treated with an equimolecular mixture of HBr & HCl, which product will be predominated product.