Question

When
$(a - b)x ^{2} + (b - c)x + (c - a) = 0 \: prove that 2a = b + c$
​

Answer 1

$= (a - b) {x}^{2} + (b - c)x + (c - a) \\ = a {x}^{2} - b {x}^{2} + bx - cx + c - a \\ =$

.

Answer 2

hope this answer will help you.