when the digit of a two digit number is reversed it becomes 5/6 of itself.Find the number if its tens digit is one more than the unit digit
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let u=units digit
let t=tens digit
t=u+1
..
(10u+t)/(10t+u)=5/6
(10u+u+1)/(10(u+1)+u)=5/6
(11u+1)/(10u+10+u)=5/6
(11u+1)/(11u+10)=5/6
66u+6=55u+50
11u=44
u=4
t=u+1=5
number=54
let t=tens digit
t=u+1
..
(10u+t)/(10t+u)=5/6
(10u+u+1)/(10(u+1)+u)=5/6
(11u+1)/(10u+10+u)=5/6
(11u+1)/(11u+10)=5/6
66u+6=55u+50
11u=44
u=4
t=u+1=5
number=54
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