Question

when the digits of two digits number are reversed the number increased by 27 the sum of such two digit number is​

Answer 1

Step-by-step explanation:

10y+x+27=10x+y

27=10x+y-10y-x

9x-9y=27

x-y=27/9=3

Answer 2

Answer:

Step-by-step explanation:

Let the two numbers by x and y. So, the two digit number will be 10x+y and when reversed it will be turned to be 10y+x. So, on adding 27 we will get that 10y+x+27=10x+y .

On solving and taking common we will get that 27=10x+y-10y-x  or 9x-9y=27 which we get  x-y=27/9=3 that is x-y=3. Now, if we take the addition of 2 numbers to be 1. Then on solving the two equations we will get the values of x and y.