Question

when the distance between two bodies of mass M1 and M2is reduced 1/3 of initial distances then the ratio of initial to final force​

Answer 1

Answer:

Ff= 9Fi

Explanation:

Fi=initial force

Ff=final force

Fi=$\frac{GM1M2}{R^{2} }$

Ff=$\frac{GM1M2}{(\frac{R}{3}) ^{2} }$

Ff=$\frac{9GM1M2}{R^{2} }$

Ff=9Fi