Question

when the electron of a hydrogen atom jumps from the n=4 to then n=1 state the number of spectral lines emitted is

Answer 1

The number of spectral lines emitted when the electron of a hydrogen atom jumps from the n=4 to then n=1 state is 6.

Explanation:

We are given:

An electron is undergoing a transition from n = 4 to n = 1.

To calculate the total number of spectral lines in the transition, we use the formula:

$N=\frac{(n_2-n_1)(n_2-n_1+1)}{2}$

where,

$n_1$ = lower energy level = 1

$n_2$ = higher energy level = 4

Putting values in above equation, we get:

$N=\frac{(4-1)(4-1+1)}{2}=6$

So, the total number of spectral lines in the transition are 6

Hence, the number of spectral lines emitted when the electron of a hydrogen atom jumps from the n=4 to then n=1 state is 6.

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Answer 2

The count of spectral line emitted is 6.

Given,

Atom jumps from n= 4 to n = 1 state.

To Find,

The number of spectral lines in the transition.

Solution,

Given that,

The hydrogen atom jumps from the state of n= 4 to n=1.

Need to find out the count of emitted spectral lines,

N =  $\frac{(n2-n1) (n2 - n1 +1) }{2}$,

n1 is a lower energy level.

n2 is the highest level of energy.

Therefore,

N = $\frac{(4-1) ( 4 - 1 + 1)}{2}$

N = $\frac{12}{2}$

N = 6.

Hence, 6 spectral lines are emitted during the transition of the atom.

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