Physics, asked by ammuvijayan59, 4 months ago

When the elevator is accelerating downwards with an acceleration ‘a’ the apparent

weight of a man standing in the elevator is

a) m(g - a) b) m(g + a) c) mg d) zero​

Answers

Answered by keshavaggarwal2310
0

Answer:

a

Explanation:

Answered by Nihalnikam
0

Answer:

when the elevator is falling freely downwards , it experience s the acceleration due to gravity (here g=a) . At such times the person standing in the elevator could not feel his own weight due to the phenomenon of weightlessness.

hence , your correct answer is zero

Similar questions