When the elevator is accelerating downwards with an acceleration ‘a’ the apparent
weight of a man standing in the elevator is
a) m(g - a) b) m(g + a) c) mg d) zero
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Answer:
a
Explanation:
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Answer:
when the elevator is falling freely downwards , it experience s the acceleration due to gravity (here g=a) . At such times the person standing in the elevator could not feel his own weight due to the phenomenon of weightlessness.
hence , your correct answer is zero
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