When the integers 10, 0, 5, -5,-7 are arranged in descending or ascending order, then
find out which of the following integers always remains in the middle of the arrangement.
(a) 0 (b) 5 (c) – 7 (d) -5
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Answer:
0
Step-by-step explanation:
The integers in ascending order:
-7 < -5 < 0 < 5 < 10
The integers in descending order:
10 > 5 > 0 > -5 > -7
Note that in both cases the number of elements on either side of 0 is same i.e 2. Therefore we see that 0 lies in the middle of the arrangement.
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