Question

When the kinetic energy of a body executing shm is 1/3 of the potential energy?

Answer 1

Answer:

Explanation:

Let the total energy be T=(1/2)*K*A^2

Let PE be p, then KE=p/3

Also we know that energy is conserved in shm.

So KE+PE=T(total energy)

p/3+p=1/2KA^2

So, p=(3/4)*(1/2)*K*A^2

We know that PE at a point in shm=1/2Kx^2

Where x is displacement from mean position.

Hence, p=(3/4)*(1/2)*K*A^2=1/2*k*x^2

So, we get (3/4)A^2=x^2

Therefore, x=(√3/2)A or -(√3/2)A

In % of amplitude it is 86.602%