Question

When the light illustrated in the diagram passes through the glass block, it is shifted literally by the distance d taking n = 1.50, find the value of d.

Answer 1

Given:

The refractive index n2 = 1.50

The refractive index in air n1= 1

To find:

The distance from shifting it.

Solution:

The refractive index formula

n1.sinФ=n2.sin∅

Putting the values

1×sin(30)=1.50×sin∅

∅=19.5

The distance h the light travels

cos∅=2.00/h

h=2.00/cos19.5

h=2.12 cm

Now calculate the angle of deviation

α=Ф-∅

α=30-19.5

=1.05

The distance of shifted is

sinα=d/h

Putting the above values

d=sinα×h

d=(2.21)sin10.5

d=0.388 cm

So the distance for the shifted is 0.388 cm