Question

When the momentum of a proton is changed by an amount p0, then the corresponding change in the de-broglie wavelength is found to be 0.25%. The original momentum of the proton was?

Answer 1

Answer:

400p.............

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Answer 2

The original momentum of the proton is 400p0.

Let p be the original momentum of the proton and p0 is the change in momentum.

de-Broglie's wavelength = λ = h/p = Planck's constant / momentum

∆p/p = ∆λ/λ , change in momentum upon the original momentum is equal to change in wavelength upon original wavelength.

=> ∆p/p = ∆λ/λ

=> p0/p = 0.25/100

=> p=400p0

The original momentum of the proton is 400p0.

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