when the number of resistance are connected in the series in a circuit what could be their equivalent resistance and why
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if we connected the number of resistor in series we get the effective resistance as R=R1+R2+R3+.....Rn
if we connect them in parallell we get the effective resistance as 1/R=1/R1+1/R2+1/R3+.......+1/Rn
we get the effective resistance becouse in series the current is same through each resistor and voltage is drops acros each
in parallell the voltage is same through the each resistor and the current is different in each
if we connect them in parallell we get the effective resistance as 1/R=1/R1+1/R2+1/R3+.......+1/Rn
we get the effective resistance becouse in series the current is same through each resistor and voltage is drops acros each
in parallell the voltage is same through the each resistor and the current is different in each
Answered by
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R=R1+R2+R3+...Rn
because in series the current flow through the each resistor is same I=i1 =i2=i3=...in- 1eq
and total voltage is equal to the sum of the voltages
V=v1+v2+v3...Vn -2eq
according to ohms law v=IR
sub in 2equation
IR=IR1+IR2+IR3+..IRn
IR=I(R1+R2+R3+..Rn)
R=R1+R2+R3+..Rn
because in series the current flow through the each resistor is same I=i1 =i2=i3=...in- 1eq
and total voltage is equal to the sum of the voltages
V=v1+v2+v3...Vn -2eq
according to ohms law v=IR
sub in 2equation
IR=IR1+IR2+IR3+..IRn
IR=I(R1+R2+R3+..Rn)
R=R1+R2+R3+..Rn
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