Question

when the number
${3}^{98}$
is divided by 5 the remainder is

Answer 1

Remainder [3^98 / 5]

= Remainder [ 9^49 / 5]

= Remainder [ (-1)^49 / 5]

= Remainder [ (-1)/5] = 4

Answer 2

Answer:

Remainder = 4

Step-by-step explanation:

Given question can be easily determined by the remainder theorem

Remainder [3^98 / 5]

Remainder [ (3²)^49 / 5]

Remainder  (9^49/5)

Find out the nearest number that leaves remainder to simplify the equation,

= Remainder [ (-1)^49 / 5]

= Remainder [ (-1)/5] = -1 or 4 is the remainder, since the remainder can not be negative so answer is 4.