Question

When the pressure is applied to one liter of a liquid is increased by 2×10^6 N/m^2, its volume decrease by 10^-6m^3. Find the bulk modulus of liquid

Answer 1

answer : bulk modulus of liquid is 2 × 10^9 N/m²

pressure change , ∆P = +2 × 10^6 N/m²

change in volume, ∆V = - 10^-6 m³

initial volume , V = 1 Litre = 10^-3 m³

we know,

bulk modulus, β = -∆P/(∆V/V)

= - (2 × 10^6 N/m²)/(-10^-6 m³/10^-3 m³)

= 2 × 10^6 N/m² /10^-3

= 2 × 10^9 N/m²

hence, bulk modulus of liquid is 2 × 10^9 N/m²

also read similar questions : Find the increase in pressure required to decrease volume of mercury by 0.001%. (Bulk modulus of mercury = 2.8 x 10¹⁰ N ...

https://brainly.in/question/6930049

The increase in pressure required to decrease the 200 L volume of a liquid by 0.008% in kPa is (Bulk modulus of the liqu...

https://brainly.in/question/6891365

Answer 2

$\huge\star\mathfrak\blue{{Answer:-}}$

pressure change , ∆P = +2 × 10^6 N/m²

change in volume, ∆V = - 10^-6 m³

initial volume , V = 1 Litre = 10^-3 m³

we know,

bulk modulus, β = -∆P/(∆V/V)

= - (2 × 10^6 N/m²)/(-10^-6 m³/10^-3 m³)

= 2 × 10^6 N/m² /10^-3

= 2 × 10^9 N/m²

hence, bulk modulus of liquid is 2 × 10^9 N/m²