When the pressure on a given mass of liquid is increased from 3.0 MPa to 3.5 MPa, the density
of the liquid increases from 500 kg/m to 501 kg/m'. What is the average value of bulk
modulus of the liquid over the given pressure range? ILJIET] Ans: - 250MPa
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Answered by
8
Bulk modulus,
K=ρ*dp/dρ
=(500 x(3.5-3.0)) /(501-500)
=250 MPa
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Answered by
4
Answer:
250 MPa
Explanation:
As per the data given,
Pressure increases from 3 MPa to 3.5 MPa,
and density increases from 500kg/m to 501kg/m.
We have,
Bulk modulus(K) = volume stress/ volume strain
and also we have
K ∝ dp
i.e. if pressure increases bulk modulus also increases.
so,
K = ΔP/(ΔV/V°)
now, multiplying and dividing by mass (m)
∴ density = mass / volume
We get,
K= ΔP/(Δd/d).
now ,
K = (3.5 - 3.0 )/ (500-501/500)
K = 0.5*500 MPa
K = 250MPa
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