When the radius of a circle is 8 cm and the angle subtended by a chord at the centre of the circle is 30°, prove that the area of the corresponding minor segment of the circle is 16(π/3-1)cm².
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Answer:10 cm
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Answer= 16(pi-root3/3)
Explanation
Radius=8 cm
Theta =30
Area of minor segment = area of sector - area of triangle
Area of sector= theta/360 x pi x r^2
= 30/360 x pi x 8 x8
=1/12 x pi x 8 x 8
= 8 x 8 x pi/12
=64 x pi/12
= 16 x pi/3
Area of triangle = root 3/4 x a^2
= root3/4 x 8 x 8
=root3/4 x 64
=root3 x 16
=16root3
Area of sector-area of triangle
= 16/3 x pi - 16root3
=16(pi-root3/3)
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Explanation
Radius=8 cm
Theta =30
Area of minor segment = area of sector - area of triangle
Area of sector= theta/360 x pi x r^2
= 30/360 x pi x 8 x8
=1/12 x pi x 8 x 8
= 8 x 8 x pi/12
=64 x pi/12
= 16 x pi/3
Area of triangle = root 3/4 x a^2
= root3/4 x 8 x 8
=root3/4 x 64
=root3 x 16
=16root3
Area of sector-area of triangle
= 16/3 x pi - 16root3
=16(pi-root3/3)
Mark as brainliest and thank me..................
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