when the son will be as old as his father today,the sum of their ages then will be 126. When father was as old as his son today, the sum of their ages then was 38 . Find their present ages
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father 's new age+ son 's new age= 126
[y+(y-x)] + [(x + (y-x))] = 126
⇒ 2y - x + y = 126
∴ 3y - x = 126 ---(1)
father 's previous age+ son 's previous age = 38
⇒ [y - (y-x)] + [x - (y-x)] = 38
⇒ x + x - y + x = 38
⇒ 3x - y = 38
∴ y = 3x - 38---(2)
Now subtract equation(2) from equation 1
⇒ 3(3x-38) - x = 126
⇒ 9x - 114 - x = 126
⇒ 8x = 240
therefore, x = 30
Now y = 3x - 38
⇒ y = 3(30) - 38
therefore, y = 52
Therefore,the son is 30 years old, and the father is 52 years old.
Jhope it helps <3
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