Question

when the son will be as old as the father today their ages will add up to 126 years.when the father was old as the son is today,their
r ages upto 38 years.then what will be present ages:​

Answer 1

Step-by-step explanation:

Let x = son's current age

Let y = father's current age

Equation 1 (we have to go forward (y-x) years, so we add the (y-x) terms):

[Father's new age] + [Son's new age] = 126

[y+(y-x)] + [(x + (y-x))] = 126

2y - x + y = 126

3y - x = 126

Where does the(y-x) term come from? Well, it says 'when the son will be as old as the father is today', which means that the son has to age a certain amount of years. How many years does he have to age? The difference between his current age and his father's current age. For example, if the son was 10 and the father was 40, it would take the son 30 years (or y-x = 40-10) to reach his current age. In the meantime, the father would age the same amount (y-x=40-10=30 years).

Equation 2 ( we have to go back (y-x) years, so we subtract the (y-x) terms ):

[Father's previous age] + [Son's previous age] = 38

[y - (y-x)] + [x - (y-x)] = 38

x + x - y + x = 38

3x - y = 38

y = 3x - 38

Now sub this value of y into Equation 1:

3(3x-38) - x = 126

9x - 114 - x = 126

8x = 240

x = 30

y = 3x - 38

y = 3(30) - 38

y = 52

The son is 30 years old, and the father is 52 years

mark me braniest plzzz and follow me