Question

When the voltage drop across a p-n junction diode is increase from 0.65 v to 0.70 v, the change in the diode current is 5mA. What is the dynamic resistance of the diode? ​

Answer 1

Answer:

That's very very basic question.

$v2 - v1 = .5 \\ i = 5 \times {10}^{ - 3} \\ therefore \: r = 0.5 \div 5 \times {10}^{ - 3}$

$= 100$

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