Question

when two balanced dice are rolled simultaneously,the probability of getting the sum of numbers on dice as 9 is
(1/9,
1/6,
1/12
,1/18)​

Answer 1

Answer:

1/9 is your correct answer

Step-by-step explanation:

hope it's helpful

Answer 2

Given:

Two balanced dice are rolled

To Find:

The probability of getting the sum of numbers on dice as 9 is

Solution:

when two dice are thrown then sample space will be:

S = { (1,1) (1,2) (1,3) (1,4) (1,5) (1,6) (2,1) (2,2) (2,3) (2,4) (2,5) (2,6) (3,1) (3,2) (3,3) (3,4) (3,5) (3,6) (4,1) (4,2) (4,3) (4,4) (4,5) (4,6) (5,1) (5,2) (5,3) (5,4) (5,5) (5,6) (6,1) (6,2) (6,3) (6,4) (6,5) (6,6) }

n(S) = 36

Event of getting sum equal to 9 =

= (3,6) (4,5) (5,4) (6,3)

n(9) = 4

so,

Probabilty of getting sum 9 equal to= n(9)/n(S)

= 4/36

=1/9

Hence, the probability of getting the sum of numbers on dice as 9 is 1/9.