Question

When two coins are tossed find the probability of atleast one had and atmost one head?

Answer 1

total no. of outcomes = (H T ) (H H) (T T) (T H)

prob. of getting atleast one head = no. of outcomes / total no. of outcomes

= 3 / 4

prob. of getting atmost one head = no. of outcomes / total no. of outcomes
= 3/4