when two conductor are connected in series, their equivalent resistance is 25 ohm, but when they are connected in parallel, their equivalent resistance is 4ohm. calculate the resistance of conductors.
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R1+R2=Req.
Req.=25
R1+R2=25.
R2= 25-R1
1/R1+1/R2= 4 ohm
R1R2 /(R1+R2)= 4
4(R2+R1)= R1R2
After putting the value of R2:-
(25-R1)R1= 4(25)
25R1-R1^2= 100
R1^2- 25R1-100= 0.
R1^2-20R1-5R1-100=0
R1(R1-20) +5(R1-20)=0
R1= 20
R2 =5
OR
R1=5 ohm ,R2=20 Ohm
Req.=25
R1+R2=25.
R2= 25-R1
1/R1+1/R2= 4 ohm
R1R2 /(R1+R2)= 4
4(R2+R1)= R1R2
After putting the value of R2:-
(25-R1)R1= 4(25)
25R1-R1^2= 100
R1^2- 25R1-100= 0.
R1^2-20R1-5R1-100=0
R1(R1-20) +5(R1-20)=0
R1= 20
R2 =5
OR
R1=5 ohm ,R2=20 Ohm
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