When two dice are thrown simultaneously, what is the probability of getting the sum of the
numbers that appear on the top is more than 10?
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We have apply the rule of Probability. First draw the table and see the possible outcomes. Make it something like the table below. Then examine the table. 10 is only possible 3 times according to the table out of 36 outcomes. SO the answer is 3/60,which is 1/20 when further simplified. If this helps vote it the Brainiest answer.
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A is the event of getting sum of nos more than 10
n(S)=36
A={(5,6),(6,4),(6,5),(6,6)} n(A)=4
P(A)=n(A)/n(S)=4/36=1/9
hence when 2 dice are thrown,prob of getting sum of numbers that appear on the top is more than 10 =1/4
n(S)=36
A={(5,6),(6,4),(6,5),(6,6)} n(A)=4
P(A)=n(A)/n(S)=4/36=1/9
hence when 2 dice are thrown,prob of getting sum of numbers that appear on the top is more than 10 =1/4
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