Question

when two numbers are separately devid by 33 remainder are 21 and 28 respectively sum of two numbers divided by 33 reminder will be​

Answer 1

Answer:

smallest such numbers which when divided by 21 and 28 leaves the given remainder of 21 and 28 could be for the value of a=0 and b=0, i.e 21 and 28. So, irrespective the value of 'a' and 'b' , 33(a+b) will always be divisible by 33.