When two resistors of resistances R1 and R2 are connected in parallel, the net resistance is 3 W . When connected in series, its value is 16 W . Calculate the values of R1 and R2 .
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1
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Explanation:
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Resistance equivalent in parallel is given by R1 *R2 / (R1+R2)
Resistance equivalent in series is R1 + R2
Given R1 + R2 = 16
and R eq in parallel as 3
sustitute the above values in the first equation of parallel equivalence
we get R1*R2 = 3*16 = 48
The values of R1 and R2 are 12,4
By using basic calculations of (R1-R2)^2 = (R1 +R2)^2 - 4R1R2
R1 - R2 = sqrt(256-192) = sqrt(64) = 8
solving R1 and R2 we get r1 =12 and r2 =4
Answered by
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AnswEr :
Let the resistors be R and r
When the resistors are connected in series,
When the resistors are connected in parallel,
We know that,
Thus,
Adding equations (1) and (2),
Putting value of R equation in equation (2),
Thus,both the resistors are 12Ω and 4Ω
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